what is the magnitude of the potential difference δv14?
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The relationship between an uniform electric field →E, potential difference between points AandB (Δϕ), and distance d between them is:→E=−Δϕd.−ve sign indicates that a positive charge will be repelled away from the positively charged plate, towards higher-voltage. This expression can be re-written as
Δϕ=−→E⋅→dor Δϕ=−∣∣∣→E∣∣∣∣∣∣→d∣∣∣cosθAssuming that the electric field has component only along the distance vector and also it is uniform, cosθ=cos0=1. We obtain
|Δϕ|=∣∣∣→E∣∣∣∣∣∣→d∣∣∣Inserting given values after converting distance in to meters,Δϕ=3.7×107×0.60103=2.22×104V